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Welcome Guide to Swift 5 Escaping String

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With the evolution of Swift, we often comes to create strings from raw text which can be a pain. Properly escaping any quotes or backslash characters in the raw text is an exercise in frustration. Swift 5, introduced with Xcode 10.2, introduces a new syntax to make it easier to work with raw text. Traditional Strings With String Literals To create a String from literal text, we use the common method of double quote (") as a starting and ending delimiter and the backslash (\) to escape special characters. For example, to create a String that preserves the double-quotes in this text: let title1 = "This is \"title\" here" // This is "title" here Swift 5 Custom String Escaping Swift 5 allows you to customize the delimiter and escape sequences. This is useful when working with raw text that might contain the delimiters or multiple escape sequence. Here we can pad the start, end and escape delimiters with one or more “ # ” characters....
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Movie review on 'Jobs' biopic in opening weekend

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          Failing worse than the Newton handheld PDA, the biopic Jobs opened this weekend on 2381 screens, bringing in an estimated $6.7 million. The movie's distributor, Open Road Films, was hoping to sell $8 million to $9 million in tickets for the opening weekend. But with Steve Wozniak criticizing the truthfulness of the story, it would seem that even Apple fans stayed away from the movie. Starring Ashton Kutcher as Steve Jobs and Josh Gad as the Woz, Jobs garnered a aggregate score of 25% from the reviews on Rotten Tomatoes. But even with the poor turnout at the theaters, Jobs still could turn a profit since the budget for the movie came in at $12 million. After DVD sales and television rights, the movie should surpass its budget. Another movie about the late Apple co-founder is in the works, written by Aaron Sorkin and produced by Sony. This film is expected to be in three acts with each act showing Jobs backstage before the introduction of an Appl...
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Java Program for protocol 2 with two way communication between sender and receiver until receiver response some signal.

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//sender to send message for protocol 1 import java.io.*; import java.net.*; public class protocol2_Sender { public static void main(String args[]) { try { Socket s=new Socket("localhost",6666); DataOutputStream dos=new DataOutputStream(s.getOutputStream()); DataInputStream dis=new DataInputStream(s.getInputStream()); BufferedReader br= new BufferedReader(new InputStreamReader(System.in)); String str="",signal=""; do { System.out.println("Sender: "); str=br.readLine(); System.out.println("String: "+str); dos.writeUTF(str); //dos.writeUTF(ch); //dos.flush(); signal=dis.readUTF(); System.out.println("Server says: " +signal); }while(signal.equals("signal")); //dos.flush(); dos.close(); //s.close(); } catch(IOException e) { System.out.println(e.getMessage()); } } } //receiver to...
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